why
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I was reading it as saying that since it includes every possible number combination then simply representing it in base 2 (for example) gives both the digits necessary to represent all possible combinations of numbers since you have infinitely many 1s and 0s to choose from.
It says that the decimal expansion of pi necessarily includes every possible digit combination by virtue of the fact it is an infinite, non-repeating series of digits. This is wrong, and trivially so— you can construct an infinite non-repeating sequence using only the digits 0-8, that necessarily won't include any digit sequences that contain any 9s. Pi also doesn't include any infinitely repeating rational-number decimal expansions, or else it would be rational itself.
As it happens, mathematicians seem to think the decimal expansion of pi includes all finite sequences of digits, but there's no reason simply to assume this to be the case.
I was reading it as saying that since it includes every possible number combination then simply representing it in base 2 (for example) gives both the digits necessary to represent all possible combinations of numbers since you have infinitely many 1s and 0s to choose from.
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