pls solve this math question...

gdl203 · Jun 25, 2009

AB = 2,300
BC = 2πR * 16 = π*13*16 = 653.45
AC = ?

ABÂ² = BCÂ² + ACÂ²
2,300Â² = (653.45)Â² + ACÂ²
ACÂ² = 2,300Â² - (653.45)Â²
ACÂ² = 5,290,000 - 426,999
ACÂ² = 4,863,001
AC = 2,205 cm = 22.05 m

TheFoo · Jun 25, 2009

Originally Posted by gdl203

AB = 2,300
BC = 2πR * 16 = π*13*16 = 653.45
AC = ?

ABÂ² = BCÂ² + ACÂ²
2,300Â² = (653.45)Â² + ACÂ²
ACÂ² = 2,300Â² - (653.45)Â²
ACÂ² = 5,290,000 - 426,999
ACÂ² = 4,863,001
AC = 2,205 cm = 22.05 m

That looks right, right?

Right?

gdl203 · Jun 25, 2009

Originally Posted by mafoofan

That looks right, right?

Right?

What, the angle?

Hany · Jun 25, 2009

Here's my math:
Perimeter is Pi*D=0.4084070449666731m
For each revolution we have: 23m of string/16=1.4375m
With Pythagoras we have: 1.4375^2=X^2 + 0.4084070449666731^2
Where X is the side of each triangle
Then multiply X by 16 and get 22.05221402760111m or 22.05 m

Hany · Jun 25, 2009

And ^ confirms the rest of the posters' math. I'm pretty sure that's correct.

sho'nuff · Jun 25, 2009

Originally Posted by HomerJ

I got a C- in vector calculus so I shouldn't answer.

heck i withdrew from my calculus classes and changed majors.

alan · Jun 25, 2009

I dont get it. What does the length of the wire have anything to do with it....

Shouldnt we know its thickness? If its assumed to be infinitely small then you could wrap an infinitely long wire and only reach an infitely small height down the pole. Or am i missing something?

If you wrap a 1m thick 2 m long cable 16 times down a pole youre gonna get a very different height than wrapping a 2m thick 2m long cable down.

Im prob. missing something

CunningSmeagol · Jun 25, 2009

Originally Posted by alan

I dont get it. What does the length of the wire have anything to do with it....

Shouldnt we know its thickness? If its assumed to be infinitely small then you could wrap an infinitely long wire and only reach an infitely small height down the pole. Or am i missing something?

If you wrap a 1m thick 2 m long cable 16 times down a pole youre gonna get a very different height than wrapping a 2m thick 2m long cable down.

Im prob. missing something

This would look like an impressive dump, befitting a progressive chocolate company. Nicely done.

gdl203 · Jun 25, 2009

I believe the assumption is that the thickness of the wire is not a significant variable, i.e. calculate assuming wire is a line, not a cylinder

alan · Jun 25, 2009

Originally Posted by gdl203

I believe the assumption is that the thickness of the wire is not a significant variable, i.e. calculate assuming wire is a line, not a cylinder
Yeah but a line does not have a thickness so if youre stacking a wrapped line 16 times on top of itself, it will not produce any length down the pole?

alan · Jun 25, 2009

For example:

a 2m thick 23 m cable would need x height to wrap 16 times around a pole

a 1 cm wire of the same length would need way less height to wrap 16 times.

No?

a line would need infitely small height to wrap.

Maybe the first two would even out by factoring in that the number of revolutions would be greater for the second, but my example was to show that an infitely small thickness 16 times will not produce any length down the pole?

Douglas · Jun 25, 2009

alan: is not tight wrap. string have space between coils, like spring.

gdl203 · Jun 25, 2009

Originally Posted by alan

Yeah but a line does not have a thickness so if youre stacking a wrapped line 16 times on top of itself, it will not produce any length down the pole?

Not on top of itself, around the pole and down to the ground. Wire goes from A to B on the Pythagore triangle

Douglas · Jun 25, 2009

Originally Posted by gdl203

Not on top of itself, around the pole and down to the ground. Wire goes from A to B on the Pythagore triangle

It's Pythagoras, Frenchie.

alan · Jun 25, 2009

Originally Posted by Douglas

alan: is not tight wrap. string have space between coils, like spring.

Then how can you calculate without knowing the space between the coils?

If you increase the space you can cover a lot more height using the same length wire no?

pls solve this math question...

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